wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question


lf (0,52) is a centre of similitude for the circles x2+y2+6x2y+1=0 and x2+y22x6y+9=0 then the length of the common tangent of the circles through it is

A
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 2

From Point (1),
n2+y2+6x2y+1=0
r1=3
C1(3,1)
x2+y22x6y+9=0
r2=1
C2(1,3)

From Point (11),
P(0,52)
& Q(62,82)
Q(3.4)
P is intersection of internal common tangent
So,
length of tangent =S1+S2
=94+14
=32+12
=2


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative Motion in 2D
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon