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Question

lf 0<a<b, then ba|x|xdx=

A
ab
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B
a+b
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C
0
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D
ba
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Solution

The correct option is D ba
a<a<b ba|x|xdx
ba1dx=(ba)
ba|x|xdx=(ba)
64837_30938_ans_8eef8c53af5842a39c9dfe05d4bf4cad.png

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