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Question

lf (1,2) and (3,4) are limiting points of the given coaxial system then the least circle belonging to the orthogonal coaxial system is x2+y2+ax+by+c=0. Then (a,c)=

A
(4,11)
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B
(6,11)
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C
(4,11)
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D
(4,11)
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Solution

The correct option is A (4,11)
(1,2) and (3,4) are limiting point of coaxial system
for least circle belonging to this system has centre
mid-point of limiting point.
So, (2,3) is a centre of circle
(x2)2+(y3)2=(12+12)2
x2+y24x6y+13=2
x2+y24x6y+11=0
So, a=4 and c=11
(a,c)=(4,11)

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