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Question


lf (1+x)(1+x+x2)(1+x+x2+x3)+(1+x+x2+..xn1)=ao+a1x+a2x2+..ammxm, then a0+a1+a2++am=

A
m!
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B
n!
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C
(m!)2m!n!
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D
n
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Solution

The correct option is B n!
We have,
(1+x)(1+x+x2)(1+x+x2+x3).+(1+x+x2+..xn1)=ao+a1x+a2x2+..amxm
Put x=1 both sides we get,
a0+a1+a2++am=(1+1)(1+1+1)(1+1+1+1)........(1+1+1..............n times)
=(1+1)(1+1+1)(1+1+1+1)........(1+1+1..............n times)
=2×3×4×5...............×n

=1×2×3×4×5.........×n=n!

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