The correct option is D All of these
It is given that 24x is a multiple of 3
∴2+4+x is a multiple of 3
⇒6+x is a multiple of 3
⇒6+x=0,3,6,9,12,15,......(1)
But x is a digit of the number 24x
∴x can take value 0,1,2,....,9
⇒6+x can take values 6,7,8,...,15...(2)
From (1) and (2), we get
6×x=6 or 9 or 12 or 15
⇒6+x=6 or 6+x=9, or 6+x=12 or 6+x=15
⇒x=0 or x=3, or x=6 or x=9
Hence, x=0,3,6,9.