lf (9+√80)n=I+F, where I is odd and 0<F<1, then I−F=
A
1
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B
(9−√80)n
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C
(9+√80)n
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D
4
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Solution
The correct option is A(9−√80)n Since (I−F)(I+F)=1 ...(identity) I−F=1I+F Hence (I−F)(I+F)=1 Therefore (I−F) =((9+√80)n)−1 =((9+√80)−1)n =(9−√80)n Hence answer is B.