Lf A- 0 2- 3 -4 -kA- 0 3a- 2b 24 - then the values of k-a-b are

If $A = [\begin{matrix} 0 & 2 3 & - 4 \end{matrix}]$ , $k A = [\begin{matrix} 0 & 3 a 2 b & 24 \end{matrix}]$ ,then the values of k, a, b respectively are ______ .

Q. If

A = [\begin{matrix} 0 & 2 3 & - 4 \end{matrix}]

and

k A = [\begin{matrix} 0 & 3 a 2 b & 24 \end{matrix}]

, then the values of k, a, b are respectively.

Join BYJU'S Learning Program

lf A=[023−4],kA=[03a2b24], then the values of k,a,b are

The correct option is C −6,−4,−9Since, kA=[02k3k−4k]=[03a2b24]Comparing the elements give us −4k=24⇒k=−6Therefore, 3a=2k=2(−6)⇒a=−4Similarly, b=−9.

lf $A = [\begin{matrix} 0 & 2 3 & - 4 \end{matrix}], k A = [\begin{matrix} 0 & 3 a 2 b & 24 \end{matrix}]$ , then the values of $k, a, b$ are

The correct option is C $- 6, - 4, - 9$
Since, $k A = [\begin{matrix} 0 & 2 k 3 k & - 4 k \end{matrix}] = [\begin{matrix} 0 & 3 a 2 b & 24 \end{matrix}]$
Comparing the elements give us $- 4 k = 24$
$\Rightarrow k = - 6$
Therefore, $3 a = 2 k = 2 (- 6)$
$\Rightarrow a = - 4$
Similarly, $b = - 9$ .