Lf A- 1 2 1- 3 4 2- 1 3 2 - and B- 10 -4 -1- -11 5 0- 9 -5 1 - then

The correct option is A AB=BA Given, A=[ 1 amp; 2 amp; 1; 3 amp; 4 amp; 2; 1 amp; 3 amp; 2 ], B=[ 10 amp; 4 amp; 1; 11 am ...

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Transpose of a Matrix

lf A=[ 1 2 ...

Question

lf $A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 1 3 & 4 & 2 1 & 3 & 2 \end{matrix} ⎤ ⎥ ⎦$ and $B = ⎡ ⎢ ⎣ \begin{matrix} 10 & - 4 & - 1 - 11 & 5 & 0 9 & - 5 & 1 \end{matrix} ⎤ ⎥ ⎦$ then

A B = B A

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A B = - A B

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A B = 2 B A

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A B = 3 B A

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