Question

lf a circle cuts three circles $S=0,S^{\prime }=0$ and $S^{\prime \prime }=0$ orthogonally, then its equation is

• A. ${\lambda }_{1}S+{\lambda }_2{S}^{\prime }+{\lambda }_3{S}^{\prime \prime }=0$
• B. ${\lambda }_{1}S+{\lambda }_2{S}^{\prime }=0$
• C. ${\lambda }_1{S}^{\prime }+{\lambda }_2{S}^{\prime \prime }=0$
• D. ${\lambda }_{1}S+{\lambda }_2{S}^{\prime \prime }=0$

Answer 1

Answer: (A)

${\lambda }_{1}S+{\lambda }_2{S}^{\prime }+{\lambda }_3{S}^{\prime \prime }=0$

Concept $\to e{q}^n$ of circle cutting three circle $s=0.s^{\prime }=0$ and $s^{\prime \prime }=0$, orthogonally
It is given by ${\lambda }_{1}S+{\lambda }_2{S}^{\prime }+{\lambda }_3{S}^{\prime \prime }=0$