lf α,β are the real roots of the equation ax2+bx+c=0, then the value of (1+α+α2)(1+β+β2) is
A
positive
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B
negative
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C
non-negative
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D
non-positive
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Solution
The correct option is B positive If we see the expression (1+α+α2)(1+β+β2) The discriminant of both the expressions (1+α+α2) & (1+β+β2) is less than zero, which means the expression will always give a positive value more than zero . So, the expression will always be positive . Option A is correct .