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Question

lf α, β are the roots of ax2+bx+c=0, then the value of (βaα+b)4(αaβ+b)4 is

A
0
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B
1aa4
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C
1+aa3
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D
1+aa2
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Solution

The correct option is A 0
α,βaretherootsoftheequationax2+bx+c=0aα2+bα+c=0(aα+b)α=caα+b=cα(1)Similarlywithβasarootwehaveaβ+b=cβ(2)From(1)and(2)andthegivenexpressionwehave⎜ ⎜βcα⎟ ⎟4⎜ ⎜ ⎜αcβ⎟ ⎟ ⎟4=(αβc)4(αβc)4=0AnswerOptionA

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