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Question

lf α,β,γ are the roots of x3+2x2+3x+4=0, then Σα2(β+γ)=

A
6
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B
12
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C
12
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D
6
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Solution

The correct option is C 6
As α,β,γ are roots of x3+2x2+3x+4=0 gives
α+β+γ=2αβ+βγ+γα=3αβγ=4

Now,
α2(β+γ)=(α+β+γ)(αβ+βγ+γα)3αβγ=(2)(3)3(4)=6

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