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Question

lf α, β, γ are the roots of x3+x2+x+1=0 then α3+β3+γ3=

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Solution

The correct option is A 1
Given equation x3+x2+x+1=0 has roots α,β,γ
Substitute them in equation
We get α3=[(α)22αβ+α+3]
α=[11+3]
α=1

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