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Question

lf cosα is a root of 25x2+5x12=0 and (1<x<0), then the value of sin2α=

A
1225
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B
1225
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C
2025
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D
2425
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Solution

The correct option is D 2425
We can write the equation as (5x+4)(5x3)=0
Now x lies between 0 and 1 so cosα=45
Hence, sinα=35
sin(2α)=2(45)(35)=2425
Option D is correct.

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