Lf -2 and - then tan- is equal to

The correct option is D (tanβ+2tanγ) Given α +β =π #160; 2 and #160; #160; #160; β +γ =α #160; ⇒α =π #160; 2 β ⇒tanα # ...

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Sin(A+B)Sin(A-B)

lf α+β=π/2 ...

Question

lf $α + β = \frac{π}{2}$ and $β + γ = α$ , then $tan α$ is equal to

2 (tan β + tan γ)

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(tan β + tan γ)

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(tan β + 2 tan γ)

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(

2 tan β + tan γ

)

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