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Question

lf α+β+γ=π2 and cotα,cotβ,cotγ are in A.P., then the value of cotα.cotγ is

A
1
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B
2
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C
3
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D
4
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Solution

The correct option is C 3

cotα,cotβ,cotγ are in A.P.
2cotβ=cotα+cotγ=tanα+tanγtanαtanγ
2cotβ=tan(α+γ)(1tanαtanγ)tanαtanγ
2cotβ=cotβ(1tanαtanγtanαtanγ)
Let tanαtanγ=k
2=1kk
3k=1
tanαtanγ=k=13
cotαcotγ=3


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