lf $e - e^{sin x} - 4 = 0$ , then $x$ has

one real value

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no real value

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infinitely many real values

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two real values

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Solution

The correct option is D no real value
$e - e^{sin x} - 4 = 0$
$\Rightarrow e^{sin x} = e - 4$
$e - 4 < 0$ ; but $e^{sin x} > 0$ for all $x$
$∴$ It has no real roots

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