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Question


lf f(x)=xx2+x3x4+.. when |x|<1, then the ascending order of the following is
a) f(1/2)
b) f1(1/2)
c) f(1/2)
d) f1(1/2)

A
a, b, c, d
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B
c, d, a, b
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C
b, a, d, c
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D
d, c, a, b
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Solution

The correct option is B c, d, a, b
f(x)=xx2+x3x4
f(x)=x1+x(x)<1
f(12)=13
f(12)=1
f(x)=x1+x
y=x1+x
y+xy=x
y(u1)=x
f1x=xx1
f1(12)=1
f1(12)=13

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