lf f(x)=x−x2+x3−x4+…..∞ when |x|<1, then the ascending order of the following is a) f(1/2) b) f−1(1/2) c) f(−1/2) d) f−1(−1/2)
A
a, b, c, d
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
c, d, a, b
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
b, a, d, c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
d, c, a, b
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B c, d, a, b f(x)=x−x2+x3−x4 f(x)=x1+x(x)<1 f(12)=13 f(−12)=−1 f(x)=x1+x y=x1+x y+xy=x y(u−1)=x f−1x=−xx−1 f−1(12)=1 f−1(−12)=−13