lf I1=∫102x2dx,I2=∫102x3dx,I3=∫212x2dx andI4=∫212x3dx, then
A
I1>I2
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B
I2>I1
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C
I3>I4
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D
I1>I3
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Solution
The correct option is AI1>I2 I1=∫102x2dx;I2=∫102x3dx;I3=∫212x2dx I4=∫212x2dx If ∫baf(x)>∫bag(x) then we know that f(x)>g(x) in [a,b] So, 2x3[1,2]>2x2[1,2]>2x2[0,1]>2x3[0,1] I4>I3>I1>I2 So, checking the relation I1>I2 is only correct.