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Question

lf I=aa(αsin5x+βtan3x+γcosx)dx, where α, β, γ are constants, then the value of I depends on

A
γ,a
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B
α, β, γ, a
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C
α, β,a,
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D
β
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Solution

The correct option is D γ,a
I=aa(α sin5x+β tan3x+γcosx)dx(1)
I=aa[α(sin5(x)+β tan3(x)+γcos(x))]dx
=aa[α sin5xβ tan3x+γcosx]dx(2)
(1)+(2)
2I=aaγ cosx dx
I=1/2aaγ cosx dx
So, depends on a,γ

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