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Question

lf (241k) is an nilpotent matrix of index 2, then k=

A
3
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B
3
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C
4
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D
2
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Solution

The correct option is C 2
Order of matrix is 2, so square of given matrix will be zero:

(241k)×(241k)=(08+4k2k4+k2)=(0000)

By comparing, we can say that k=2


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