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Byju's Answer
Standard XII
Mathematics
Finding Inverse Using Elementary Transformations
lf [ 2 4; -...
Question
lf
(
2
4
−
1
k
)
is an nilpotent matrix of index 2, then
k
=
A
3
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B
−
3
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C
4
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D
−
2
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Solution
The correct option is
C
−
2
Order of matrix is 2, so square of given matrix will be zero:
(
2
4
−
1
k
)
×
(
2
4
−
1
k
)
=
(
0
8
+
4
k
−
2
−
k
−
4
+
k
2
)
=
(
0
0
0
0
)
By comparing, we can say that
k
=
−
2
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0
Similar questions
Q.
If
(
2
4
−
1
k
)
is a nilpotent matrix of index
2
,
then
k
equals to
Q.
Show that
A
=
⎡
⎢
⎣
1
−
3
−
4
−
1
3
4
1
−
3
−
4
⎤
⎥
⎦
is nilpotent of index
2
.
Q.
A
=
⎡
⎢
⎣
1
2
3
1
2
3
−
1
−
2
−
3
⎤
⎥
⎦
, then A is a nilpotent matrix of index
Q.
The nilpotency index of matrix
⎡
⎢
⎣
1
2
3
1
2
3
−
1
−
2
−
3
⎤
⎥
⎦
is
Q.
Show that
A
=
[
a
b
b
2
−
a
2
−
a
b
]
is nilpotent of index
2
.
Show as above that
A
2
=
A
.
A
=
[
a
2
b
2
−
a
2
b
2
−
a
3
b
+
a
3
b
a
b
3
−
a
b
3
−
a
2
b
2
+
a
2
b
2
]
[
0
0
0
0
]
=
O
Hence,
A
is nilpotent of index
2
.
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