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Byju's Answer
Standard XII
Mathematics
Determinant
lf |[ 1 2 x...
Question
lf
∣
∣ ∣
∣
1
2
x
4
−
1
7
2
4
−
6
∣
∣ ∣
∣
is a singular matrix, then
x
is equal to
A
0
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B
1
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C
−
3
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D
3
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Solution
The correct option is
A
−
3
Given
A
=
∣
∣ ∣
∣
1
2
x
4
−
1
7
2
4
−
6
∣
∣ ∣
∣
is a singular matrix
So,
d
e
t
A
=
0
⇒
1
(
6
−
28
)
−
2
(
−
24
−
14
)
+
x
(
16
+
2
)
=
0
⇒
−
22
+
76
+
18
x
=
0
⇒
18
x
=
−
54
∴
x
=
−
3
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0
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[
x
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2
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]
is a singular matrix, then
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Q.
lf
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is
⎧
⎪
⎨
⎪
⎩
8
−
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−
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λ
⎫
⎪
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Q.
If
A
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⎡
⎢
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−
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x
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[1 mark]
Q.
i) lf the inverse of matrix
A
exist. Then matrix is non singular.
ii) lf a square, non-singular matrix
A
statisfies
A
2
−
A
+
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I
=
0
then
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−
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=
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+
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)
. Which of the following statement is correct:
Q.
State whether the following statement is true or false.
The matrix
⎡
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⎣
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0
4
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−
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⎤
⎥
⎦
is singular matrix.
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