lf m and M respectively denote the minimum and mximum of f(x)=(x−1)2+3 for x∈[−3,1] then the ordered pair (m, M) =
A
(−3,19)
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B
(3,19)
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C
(−19,3)
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D
(−19,−3)
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Solution
The correct option is C(3,19) f(x) is the sum of a square and a constant term. It will acquire minimum value when the square term becomes zero. Hence, f(x) is min at x=1 f(1)=3 The other extreme value will occur at the other end point. f(x) is max at x=−3 f(−3)=19