Lf a-0-b- then -ab-x-xdx-

The correct option is C a+b a lt;0 lt;b ∫_a^b|x|/xdx ∫_a^0( 1)dx+∫_a^b1 dx =a+b ∫_a^b|x|/xdx=a+b ...

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Summation by Sigma Method

lf a<0<b, t...

Question

lf $a < 0 < b$ , then $\int_{a}^{b} \frac{| x |}{x} d x_{=}$

b-a

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a-b

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a+b

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Similar questions

a < b < 0

\int_{a}^{b} \frac{| x |}{x} d x_{=}

0 < a < b

\int_{a}^{b} \frac{| x |}{x} d x_{=}

\frac{s i n (x - α)}{s i n (x - β)} = \frac{a}{b}, \frac{c o s (x - α)}{c o s (x - β)} = \frac{A}{B}

\neq

c o s (α - β) = \frac{a A + b B}{a B + b A} .

a < b < 0

\int_{a}^{b} \frac{| x |}{x} d x =

x, y, z

A (a, 0, 0)

B (0, b, 0)

C (0, 0, c)

(p, q, r)

Δ A B C

a x + b y + c z - d = 0

a + b + c + d =

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