wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

lf A is non-singular and (A+I)(A3I)=0 then 3A1A+2I

A
I
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2I
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6I
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 0
We have,
(A+I)(A3I)=0
A23A+A3I=0[AI=IA=A,I2=I]
A22A3I=0
Multiply both sides by A1
A2I3A1=0[AA1=I]
3A1A+2I=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Multiplication of Matrices
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon