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Question

lf n is a natural number A={5−82−3} then An=

A
(6n2n62n14n)
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B
(4+n8n2n25n)
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C
(1+4n8n2n14n)
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D
(6n8n2n14n)
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Solution

The correct option is C (1+4n8n2n14n)
A=[5823]
A=[1+48214]
=I+[4824]B
An=(I+B)n
=In+nn17^{n-1}B+nn2I^{n-1}B^2+Bn
B2=[4824][4824]
=[0000]
An=In+nB=I+nB
=[1+4n8n2n14n]

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