wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

lf P is a variable point and PQ and PR are the tangents drawn to the circle x2+y2=9. Let QR be always touching the circle x2+y2=4, then locus of P is

A
4x2+4y2=81
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2x2+2y2=81
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x2+y2=16
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x2+y2=4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 4x2+4y2=81
The diagram has 2 circles. The outer one is x2+y2=9 and the inner one is x2+y2=4.

Let P(h,k) be the required point from where tangents PQ and QR are drawn and A be the point of tangency of QR with the inner circle.

Hence, equation of QR can be found as xh+yk9=0. (from pole and polar concept)

Now, if this line has the shortest distance of 2 units from origin, it is a tangent to x2+y2=4.

2=0(h)+0(k)9h2+k2

2=9h2+k2

4=81h2+k2 (squaring both sides)

4(h2+k2)=81

Hence, the required locus is 4x2+4y2=81

844889_36084_ans_415e85f7ba6642798ad83974d9085200.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Distance Formula
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon