wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

lf x=2sintsin2t,y=2costcos2t, then the value of d2ydx2 at t=π2 is

A
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
34
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
32
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 32

dydtdxdt=2sint+2sin2t2cost2cos2t
ddt(dydx)dtdx=d2ydx2=ddt(sin2tsintcostcos2t)1(2cost2cost)
(d2ydx2)t=π2=((2cos2tcost)(costcos2t)+(sin2tsint)(sint2sin2t)(costcos2t)2(2cost2cos2t))
=(2)(1)+(1)(1)2
32


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon