wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

lf r1, r2, r3 are the radii of the escribed circles of a ΔABC and if r is the radius of its incircle then r1r2r3r(r1r2+r2r3+r3r1)=

A
0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0
r1=Δsa,r2=Δsb,r3=Δsc,r=Δs
now substitute these values in the expression in question we get
Δ3(sa)(sb)(sc)Δ3s(1(sa)(sb)+1(sb)(sc)+1(sc)(sa))
Δ3s(sa)(sb)(sc)(sc(sa)(sb)(sc))
Δ3(ss)s(sa)(sb)(sc)
=0.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Gibb's Energy and Nernst Equation
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon