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Question

lf tanβ=2sinαsinγcosec(α+γ) , then cotα,cotβ,cotγ are in

A
A.P
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B
G.P
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C
H.P
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D
A.C.P
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Solution

The correct option is A A.P

we straight away get
1cotβ=2sinαsinγsin(α+γ)
so cotβ=sinαcosγ+cosαsinγ2sinαsinγ
so 2cotβ=cotα+cotγ
so AP is correct


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