lf the binding energy of the electron in a hydrogen atom is 13.6 eV, the energy required to remove the electron from the first excited state of Li2+ is:
A
30.6 eV
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B
13.6 eV
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C
3.4 eV
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D
122.4 eV.
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Solution
The correct option is A 30.6 eV The energy of the first excited state of Li++ isE2=−Z2E0n2=−32×13.622=−30.6eV. The energy need to be given to remove the electron from the first excited state is 30.6 eV. Option A is correct.