lf the curve $x y = R^{2} - 16$ represents a rectangular hyperbola whose branches lies only in the quadrant in which abscissa and ordinates are opposite in sign but not equal in magnitude, then :

| R | < 4

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| R | > 4

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| R | = 4

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R = 0

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Solution

The correct option is B $| R | < 4$
$R^{2} - 16 < 0$
$R^{2} < 16$
$| R | < 4$

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lf the curve xy=R2−16 represents a rectangular hyperbola whose branches lies only in the quadrant in which abscissa and ordinates are opposite in sign but not equal in magnitude, then :

The correct option is B |R|<4R2−16<0R2<16|R|<4

lf the curve $x y = R^{2} - 16$ represents a rectangular hyperbola whose branches lies only in the quadrant in which abscissa and ordinates are opposite in sign but not equal in magnitude, then :

The correct option is B $| R | < 4$
$R^{2} - 16 < 0$
$R^{2} < 16$
$| R | < 4$