The correct option is B (2,1)
Comparing given equation with standard form of parabola, Y2=−4aX
X=x+2y−4,Y=2x−y−3=0,a=5
Clearly the line X=0 and Y=0 are perpendicular to each other.
And we know the vertex of the parabola Y2=4aX is (X=0,Y=0)
Thus the vertex of the given parabola will be the solution of set of
equation x+2y−4=0 and 2x−y−3=0
Solving these we get x=2,y=1
Hence the vertex of the parabola is (2,1)