lf the equation of the plane perpendicular to the z -axis and passing through the point (2,−3,4) is ax+by+cz=d then a+b+cd=
Since, the plane is perpendicular to the z axis, a=b=0
The plane passes through (2,-3,4).
So d=4c
a+b+cd=c4c=14
Consider the lines L1:x−12=y−1=z+31,L2:x−41=y+31=z+32, and the planes P1:7x+y+2z=3, P2:3x+5y−6z=4. Let ax+by+cz=d the equation of the plane passing through the point of intersection of lines L1 and L2 and perpendicular to planes P1 and P2. Match List I with List II and select the correct answer using the code given below the lists. ListIListIIPa=113Qb=2−3Rc=31Sd=4−2