Question

lf the length of the side of an equilateral triangle is 2 $\sqrt{3}$ cm then its circumradius in cm is

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

The correct option is B 2

$R=\frac{abc}{4\Delta }$

$=\frac{a^3}{4\frac{\sqrt{3}{a}^2}{4}}$...(since a=b=c , equilateral triangle)

$=\frac{2\sqrt{3}}{\sqrt{3}}$

$=2$cm.