Lf the roots of px2-2qx-r-0 and qx2-2-prx-q-0 are simultaneously real- then

The correct option is C pr=q^2 Since roots are real, ⇒ (2q)^2 4pr≥ 0 #160; #160; and #160; (2√(pr))^2 4q^2≥ 0 4q^2≥ 4pr #160; a ...

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Nature of Roots

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Question

lf the roots of $p x^{2} + 2 q x + r = 0$ and $q x^{2} - 2 \sqrt{p r} x + q = 0$ are simultaneously real, then

p = q

;

r \neq 0

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2 q = \sqrt{p r}

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p r = q^{2}

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p r = q

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Solution

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