Solving a Quadratic Equation by Factorization Method
lf the roots ...
Question
lf the roots of the equation (a2−bc)x2+2(b2−ca)x+(c2−ab)=0 are equal, then the condition is
A
a+b+c=0
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B
a3+b3+c3−3abc=0
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C
a=0 or a3+b3+c3−3abc=0
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D
b=0 or a3+b3+c3−3abc=0
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Solution
The correct option is Db=0 or a3+b3+c3−3abc=0 Condition for roots of a quadratic equation to be equal is b2=4ac ⇒(b2−ca)2=(c2−ab)(a2−bc) b4+c2a2−2ab2c=c2a2−a3b+ab2c−bc3 b(a3+b3+c3−3abc)=0 ⇒b=0ora3+b3+c3=3abc