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Reynold's Number

lf the termin...

Question

lf the terminal speed of a sphere of gold (liquid density $= 1 k g / m^{3}, d e n s i t y o f s o l i d = 5 k g / m^{3}$ ,gold density= $15 k g / m^{3})$ of the same size in the same liquid.Take $V_{s} = 4 m / s$

0.2

m / s

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0.4

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0.133

m / s

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1.14 m / s

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Solution

The correct option is D $1.14 m / s$
$V_{g} = \frac{(ρ_{s} - ρ_{l})}{(ρ_{g} - ρ_{l})} V_{s} = 1.14 m / s$

Suggest Corrections

Similar questions

= 19.5 {kg/m}^{3}

0.2 m/s

= 1.5 {kg/m}^{3}

= 10.5 {kg/m}^{3}

19.5 k g / m^{3}

0.2 m / s

1.5 k g / m^{3}

10.5 k g / m^{3}

= 19.5 {kg/m}^{3}

0.2 m/s

= 1.5 {kg/m}^{3}

= 10.5 {kg/m}^{3}

A

(density = 19.5 {kg/m}^{3})

0.2 m/s

(density = 1.5 {kg/m}^{3})

B

density = 10.5 {kg/m}^{- 3})

19.5 {g/cm}^{3})

0.2 m/s

1.5 {g/cm}^{3}

= 10.5 {g/cm}^{3})

m/s

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