lf the value of a third order determinant is 11, then the value of the determinant of $A^{- 1} =$

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1 / 11

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Solution

The correct option is C $1 / 11$
$d e t (A_{3 \times 3}) = 11$
$A A^{- 1} = I$
$∴ d e t (A) = \frac{1}{d e t (A^{- 1})}$
$∴ d e t (A^{- 1}) = \frac{1}{11}$

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