lf →a=2^i+6n^j+m^k and →b=^i+18^j+3^k are parallel to each other then the values of m,n are:
A
6,6
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B
6,1
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C
-1,6
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D
-1,-6
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Solution
The correct option is A 6,6 Since, the vector a is parallel to b, the corresponding coefficients of all the 3 components must bear the same ratio i.e 21=6n18=m3 Or, 6n=36,n=6 And m=6