Lf vectors A- and B- are given by A-5-6-3k- and B-6-2-6k- then which of the following is-are correct- aA- and B- are mutually perpendicular b Product of A-B- is same as B-A- c The magnitude of A- and B- are equal d The magnitude of A-B- is zero

The correct option is C a, d are correct A⃗=5î+6ĵ+3k̂ #160; and B⃗=6î 2ĵ 6k̂ #160; is given. #160;Now scalar product of this two vector is ...

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Byju's Answer

Standard XII

Physics

Multiplication with Vectors

lf vectors ...

Question

lf vectors $\to A$ and $\to B$ are given by $\to A = 5^i + 6^j + 3^k$ and $\to B = 6^i - 2^j - 6^k$ then which of the following is/are correct?
$a) \to A$ and $\to B$ are mutually perpendicular
$b)$ Product of $\to A \times \to B$ is same as $\to B \times \to A$
$c)$ The magnitude of $\to A$ and $\to B$ are equal
$d)$ The magnitude of $\to A . \to B$ is zero

a, d are correct

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b, c are correct

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c, d are correct

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b, a are correct

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Solution

The correct option is C a, d are correct
$\to A = 5^i + 6^j + 3^k$ and $\to B = 6^i - 2^j - 6^k$ is given.
Now scalar product of this two vector is $\to A . \to B = 5 \times 6 - 6 \times 2 - 3 \times 6 = 0$
So they are mutually perpendicular.

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lf vectors →A and →B are given by →A=5^i+6^j+3^k and →B=6^i−2^j−6^k then which of the following is/are correct?a)→A and →B are mutually perpendicularb) Product of →A×→B is same as →B×→Ac) The magnitude of →A and →B are equald) The magnitude of →A.→B is zero

The correct option is C a, d are correct→A=5^i+6^j+3^k and →B=6^i−2^j−6^k is given. Now scalar product of this two vector is →A.→B=5×6−6×2−3×6=0 So they are mutually perpendicular.

The correct option is C a, d are correct
$\to A = 5^i + 6^j + 3^k$ and $\to B = 6^i - 2^j - 6^k$ is given.
Now scalar product of this two vector is $\to A . \to B = 5 \times 6 - 6 \times 2 - 3 \times 6 = 0$
So they are mutually perpendicular.