lf x∈R and the roots of ax2+bx+c=0 are non-real complex, then the sign of a2x2+abx+ac is
A
always positive
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B
always negative
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C
always non-negative
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D
always zero
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Solution
The correct option is C always positive The equation ax2+bx+c=0 has no real roots . ⇒b2−4ac<0 Consider the expression, a2x2+abx+ac Here, Δ=a2(b2−4ac)<0 and the coefficient of x2>0 . So, this expression >0 .