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Question

lf xR and the roots of ax2+bx+c=0 are non-real complex, then the sign of a2x2+abx+ac is

A
always positive
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B
always negative
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C
always non-negative
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D
always zero
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Solution

The correct option is C always positive
The equation ax2+bx+c=0 has no real roots .
b24ac<0
Consider the expression, a2x2+abx+ac
Here, Δ=a2(b24ac)<0
and the coefficient of x2>0 .
So, this expression >0 .

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