Lf x-iy1-3-a-ib then x-a-y-b-

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Algebra of Complex Numbers

lf x+iy1/3=...

Question

lf $(x + i y)^{1 / 3} = a + i b$ then $\frac{x}{a} + \frac{y}{b} =$

a^{2} - b^{2}

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(a^{2} - b^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a^{2} - b^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a^{2} - b^{2})

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Solution

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Similar questions

The equation of the circle with center (– a, – b) and radius √a² – b² is:

c o s (i l o g \frac{a - i b}{a + i b})

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sin x - sin y = b

tan (\frac{x - y}{2})

\frac{a^{2} - b^{2}}{a^{2} + b^{2}}

sin (x - y)

\frac{2 a b}{a^{2} - b^{2}}

cos (x - y)

b / a

tan (x - y)

\frac{2 a b}{a^{2} + b^{2}}

\frac{x}{a} + \frac{y}{b} = a^{2} + b^{2}

\frac{x}{a^{2}} + \frac{y}{b^{2}} = a + b

x =

\frac{a}{b}

\frac{(a sinθ - b cosθ)}{(a \sin θ + b cosθ)}

\frac{(a^{2} + b^{2})}{(a^{2} - b^{2})}

\frac{(a^{2} - b^{2})}{(a^{2} + b^{2})}

\frac{a^{2}}{(a^{2} + b^{2})}

\frac{b^{2}}{(a^{2} + b^{2})}

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