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Question

lf y=log(x+1+x2), then y′′(0) is

A
0
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B
1
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C
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D
2
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Solution

The correct option is C 0
y=log(x+1+x2)
y=1+x1+x2x+1+x2=11+x2
y′′=12(2x(1+x2)3/2)
y′′(0)=0

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