Lf z-1-z-1 - then z4-1-z4-

The correct option is C 1 We have, z^4+1z^4 = (z^2+1z^2)^2 2 = ( ( z +1z)^2 2 ) 2 =(1 2)^2 2 = 1 ...

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Inequality

lf z+1/z=1 ...

Question

lf $z + \frac{1}{z} = 1$ , then $z^{4} + \frac{1}{z^{4}} =$ ?

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z^{4} + z^{3} + 2 z^{2} + z + 1 = 0

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