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Uses of Slaked Lime

Li, Na and ...

Question

$L i, N a$ and $K$ burn in excess of air to form:

L i_{2} O, N a_{2} O

and

K_{2} O

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L i_{2} O, N a_{2} O_{2}

and

K_{2} O

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L i_{2} O, N a_{2} O_{2}

and

K O_{2}

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L i_{2} O, N a O_{2}

and

K_{2} O_{2}

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Solution

The correct option is C $L i_{2} O, N a_{2} O_{2}$ and $K O_{2}$
$L i, N a$ and $K$ burn in excess of air to form lithium monoxide ( $L i_{2} O$ ), sodium peroxide ( $N a_{2} O_{2}$ ) and potassium superoxide ( $K O_{2}$ ) respectively.
Hence, option C is the correct answer.

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Similar questions

L i, N a

K

N a

L i

C s_{2} O < R b_{2} O < K_{2} O < N a_{2} O < L i_{2} O

N a_{2} O_{2} < K_{2} O_{2} < R b_{2} O_{2} < C s_{2} O_{2}

L i H C O_{3} < N a H C O_{3} < K H C O_{3} < R b H C O_{3} < C s H C O_{3}

N a F < N a C l < N a B r < N a l

C s_{2} O < R b_{2} O < K_{2} O < N a_{2} O < L i_{2} O

N a_{2} O_{2} < K_{2} O_{2} < R b_{2} O_{2} < C s_{2} O_{2}

L i H C O_{3} < N a H C O_{3} < K H C O_{3} < R b H C O_{3} < C s H C O_{3}

N a F < N a C l < N a B r < N a I

L i_{2} O, C a O, N a_{2} O_{2}, K O_{2}, M g O and K_{2} O

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