6
Question
Light from a hydrogen discharge tube is incident on the cathode of a photoelectric cell. The work function of the cathode surface is 4.2 eV. In order to reduced the photocurrent to zero, the voltage of the anode relative to the cathode must be made
Light from a hydrogen discharge tube is incident on the cathode of a photoelectric cell. The work function of the cathode surface is 4.2 eV. In order to reduced the photocurrent to zero, the voltage of the anode relative to the cathode must be made
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Solution
The correct option is B −9.4 V
Photoelectric Law:
E=Wo+eVo
For Hydrogen atom:E=−13.6(1n2)eV
For n=1, E=13.6 eV
13.6=4.2+eVo
Vo=−9.4V
Potential at anode =−9.4V
Photoelectric Law:
E=Wo+eVo
For Hydrogen atom:
For n=1, E=13.6 eV
13.6=4.2+eVo
Vo=−9.4V
E=−13.6(1n2)eV
For n=1, E=13.6 eV
13.6=4.2+eVo
Vo=−9.4V
Potential at anode =−9.4V
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