Light from a point source falls on a screen.if the separation between the source and the screen is increased by 1% the illuminance will decrease (nearly) by
A
0.5%
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B
1%
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C
2%
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D
4%
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Solution
The correct option is B2% Illuminance depends on inverse of area and area is proportional to r2 where is r is distance from the source to the point . illuminance∝1r2 ∂(illuminance)∂x=−2δrr hence changing distance by 1% the illuminance will differ by −2δr×100r=−2% i.e,illuminance will decrease by 2% option C is correct