CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

Light from a point source in the air falls on a spherical glass surface (μ=1.5 and radius of curvature 20cm). The distance of the light source from the glass surface is 100cm. The position where the image is formed is :

A
50cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
100cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
125cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
25cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 100cm
Given: Light from a point source in the air falls on a spherical glass surface (μ=1.5 and radius of curvature 20 cm). The distance of the light source from the glass surface is 100 cm.

To find the position where the image is formed

Solution:

As per the given criteria,

Refractive index of air, μ1=1

Refractive index of glass, μ2=1.5

Radius of curvature, R=20cm

Object distance, u=100cm

Substituting the above values in the following formula, we get:

μ2vμ1u=μ2μ1R1.5v1(100)=1.51201.5v=0.52011001.5v=2.51100v=1.5×1001.5v=100 cm

Hence the image is formed at 100cm in the denser medium.


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Thin Lenses: Point Objects
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon